A ball is thrown from an initial height of 6. With an initial upward velocity of 37 ft/s. The balls hieght os given h=6+37t-16t

Question

A ball is thrown from an initial height of 6. With an initial upward velocity of 37 ft/s. The balls hieght os given h=6+37t-16t

Answer 1

h = -16t^2 +37t +6

it's velocity = h' =-32t +37

it reaches max height when t=37/32

plug that t value back into the original equation to find the max height

it hits the ground when 0=-16t^2+37t +6

use the quadratic formula if you can't factor