Raymond B. answered 06/19/21
Math, microeconomics or criminal justice
f(x) = ab^x + c
f(3) = 5 = ab^3 + c
let a=1, c=0
5 = b^3
b = cube root of 5 = about 1.71
f(1.71) =1.71 ^3 = about 5.0002
for another base, change a or c or both
f(x) =ab^x + c, let a=1 and c= 5
then
f(x) = b^x + 5
5 = b^x + 5
b^x = 0
x = cube root of 0 = 0
b= 0
f(x) = ab^x + c
f(x) = 1(0)^x +
f(x) = 5
or
f(x) = 5b^x with a=5 and c= 0
f(3) = 5 = 5b^x
b^3 = 5/5 = 1
b = cube root of 1 = 1
f(x) =5(1)^x
f(3) = 5(1)^3 = 5