solve x^2+2x-7=0 by completing the square method produces an equation of the form (x+h)^2=k find h and k

Question

solve x²+2x-7=0 by completing the square method produces an equation of the form (x+h)²=k find h and k

Answer 1

x^2 +2x -7 = 0

x^2 +2x + 1 -7 -1 = 0

(x+1)^2 -8 = 0

vertex of the parabola is (-1,-8) h=-1, k= 8 (usually k would =-8 but the way you've phrased the problem it's 8, although you may have a typo, with = instead of -)

x^2 +2x -7 = 0

x = -2/2 + or - (1/2)(sqr4+28) = -1 + or - 2sqr2 = about -3.8 or 1.8

(x+1)^2 = 8

x+1 = sqr8 = + or - 2sqr2

x = -1 _ or - 2sqr2 = about -3.8 or 1.8