sidney has two different acid solutions A is a 50%acid solution and B is a 80% acid solution. determine how much of each solution he needs to creatre 200 ml of a 68% solution

Answer 1

.50A +. 80B = .68(200) = 136 A = amount of 50%= 200-B, B= amount of 80%

.50(200-B) + .80B = 136

68 - .5B + .8B = 36

.3B = 36

B = 36/.3 = 120 of 80%

A= 80 of 50%

50 is within 18 of 68, 80 is within 12 of 68

you need more of what's closer, 80%.