
Mark M. answered 06/11/21
Mathematics Teacher - NCLB Highly Qualified
None of the solutions are complex.
f(x) = x2(x - 3)(x - 1)
The zeros are 0 (twice), 3, and 1.
Mark M. answered 06/11/21
Mathematics Teacher - NCLB Highly Qualified
None of the solutions are complex.
f(x) = x2(x - 3)(x - 1)
The zeros are 0 (twice), 3, and 1.
Dayv O. answered 06/11/21
Caring Super Enthusiastic Knowledgeable Pre-Calculus Tutor
edited from similar answer
f(x)=(x-0)*(x-0)*(x-3)*(x-1) and no root includes square root -1
maybe it could be said that since x=0 is a repeated root
x=0+0*√-1 and x=0-0*√-1 are complex conjugate roots of
f(x)= x^4−4x^3+3x^2
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