Raymond B. answered 06/11/21
Math, microeconomics or criminal justice
profit maximizing price = $270
q= -6p + 3060
-6p = q - 3060
p = 510 - q/6
Revenue = pq = 510q - (1/6)q^2
Marginal Revenue =MR = R' = 510 - q/3
C=30q
Marginal Cost =MC = C' = 30
Max profit is when MR=MC
510 - q/3 = 30
-q/3 = 30-510 = 480
q = 3(480) = 1440 = profit maximizing output level
p=510 - 1440/6 = 510 - 240 = 270 = profit maximizing price
UNLESS the cost is really 30 per unit, which means 30,000,000 per 1 million units, given that 3060 was in units of one million dollars, but there must be a typo
then 510-q/3 = 30,000,000
-q/3 = 29,999,490
q = a negative output level, to maximize profit, profit max level is zero output with zero profits, which avoids losses which come with any positive out put level. Odds are the question didn't intend this problem though.