Raymond B. answered 06/10/21
Math, microeconomics or criminal justice
f(x+h) = (x+h)^2 + 2(x+h) = x^2 +2xh + h^2 +2x + 2h
subtract x^2 + 2x
leaving: 2xh + h^2 +2h
divide by h to get 2x + h + 2
this is all preparation to take the limit as h goes to zero, which leaves 2x +2, which is the derivative of f(x).
f'(x) is the derivative or slope of the quadratic curve at the point (x, f(x)) Later you learn a short cut rule to find the derivative. For x^2 +2x, bring the exponent down as a coefficient, and reduce the exponent by 1, to get 2x. derivative of 2x is just 2. So, 2x+2 is the derivative of x^2 +2x. h is a change in x, then take the limit as h goes to zero
if you work out the solution with [f(x+h) - f(x)]/h where h goes to zero, and get something different from the short cut rule, you made a mistake somewhere