Raymond B. answered 06/10/21
Math, microeconomics or criminal justice
c. y= (x^2-4)^2/3
y' = (2/3)(x^2-4)^-1/3(2x)
= (4x/3)/(x^2-4)^1/3
= 4x/3(x^2-4)^1/3
Raymond B. answered 06/10/21
Math, microeconomics or criminal justice
c. y= (x^2-4)^2/3
y' = (2/3)(x^2-4)^-1/3(2x)
= (4x/3)/(x^2-4)^1/3
= 4x/3(x^2-4)^1/3
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