a) f = s + 2
b) (s + 2) + s
c) (s + 2) + 6 + s + 6 = 44
d) s + 2 + 6 + s + 6 = 44
e) 2s + 14 = 44
f) -14 -14
g) 2s = 30
h) 2s/2 = 30/2
s = 15
i) f = s + 2
j) f = 15 + 2 = 17
Frank = f = 17 years old
Adde T.
asked 06/09/21Frank is 2 years older than Sierra. In 6 years the sum of their ages will be 44. How old is Frank now?
a) f = s + 2
b) (s + 2) + s
c) (s + 2) + 6 + s + 6 = 44
d) s + 2 + 6 + s + 6 = 44
e) 2s + 14 = 44
f) -14 -14
g) 2s = 30
h) 2s/2 = 30/2
s = 15
i) f = s + 2
j) f = 15 + 2 = 17
Frank = f = 17 years old
Penelope M. answered 06/09/21
PSU engineering major looking to tutor students in math subjects
We know that in 6 years, the sum of Frank and Sierra's ages will be 44. We should divide this number by two
44 / 2 = 22
Frank is 2 years older than Sierra. So, we subtract 1 from 22 to find Sierra's age and add one to 22 to find Frank's age.
22 - 1 = 21 (Sierra's age in 6 years)
22 + 1 = 23 (Frank's age in 6 years)
To check to make sure this is correct, we can add 23 and 21 to get 44. In order to find out how old Frank is currently, we subtract 6 from our age number of 23.
23 - 6 = 17 (years old)
In conclusion, Frank is currently 17 years old.
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