Mark M. answered 06/08/21
Tutor
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
- Let u = 2x2-9 Then du = 4xdx. So, xdx = (1/4)du
So, ∫x√(2x2-9)dx = (1/4)∫u1/2du = (1/6)u3/2 + C = (1/6)(2x2-9)3/2 + C
For the second problem, Let u = 1 + 3x4 Then du = 12x3dx. So, x3dx = (1/12)du
So, ∫x3(1+3x4)5dx = (1/12)∫u5du = (1/72)u6 + C = (1/72)(1+3x4)6 + C