The graph of y = (x-5)2 + k is a parabola opening upward with axis of symmetry x = 5.
Since (7,6) is 2 units to the right of the line x = 5 and is 6 units above the x-axis, then by symmetry,
the point (3, 6) [two units to the left of the axis of symmetry and 6 units above the x-axis] must also be on the graph.

David W.
This is intended solution logic. But to verify, you could plug in x=7 and y=6 to determine that the constant k=2. With k=2, the only point values that yield (x,6) are (3,6) [note: easy using a spreadsheet].06/05/21