In the coordinate plane line n is represented by the equation y=14x+6 what equation represents a line perpendicular to line n that also passes through the point (1,5)

Answer 1

y=14x +6

perpendicular lines have slopes = negative inverse. = -1/14

y=-x/14 + b. calculate b by plugging in the point (1,5)

5 = -1/14 + b

b = 5 + 1/14 = 5 1/14 = 21/4

y=-x/14 +21/4 is the perpendicular equation that goes through the given point (1,5)