Nicholas D. answered 06/03/21
University of Michigan PhD Graduate and Experienced STEM Tutor
If you recall the equation of a circle: (x-x1)2+(y-y1)2=r2, the x1 and y1 values are the location of the center of your circle, and r is the radius.
Mia J.
asked 06/03/21Write the equation of the circle centered at (1,−5) with radius 18.
Nicholas D. answered 06/03/21
University of Michigan PhD Graduate and Experienced STEM Tutor
If you recall the equation of a circle: (x-x1)2+(y-y1)2=r2, the x1 and y1 values are the location of the center of your circle, and r is the radius.
Kaycie V. answered 06/03/21
Experienced Math, Science, Test Prep, Career Counseling Tutor
The general equation of a circle is r2 = (x-h)2 + (y-k)2
R is the radius
(h,k) is the center
The center given in the problem is ( 1, -5 ) where h = 1 and k = -5 and r = 18
So filling out our equation:
182 = (x - 1)2 + (y - (-5))2 --> 182 = (x - 1)2 + (x + 5)2
(x - 1)2 + (y + 5)2 = 324
Raymond B. answered 06/03/21
Math, microeconomics or criminal justice
(x-1)^2 + (y+5)^2 = 18^2
general form of the circle's equation is
(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r=radius
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