Mark M. answered 06/03/21
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Retired math prof. Very extensive Precalculus tutoring experience.
cos(x - 2π/3) = cosxcos(2π/3) + sinx sin(2π/3) = -(1/2)cosx + (√3/2)sinx
Mia J.
asked 06/03/21Rewrite cos(x−2π/3) in terms of sin(x) and cos(x)
Mark M. answered 06/03/21
Retired math prof. Very extensive Precalculus tutoring experience.
cos(x - 2π/3) = cosxcos(2π/3) + sinx sin(2π/3) = -(1/2)cosx + (√3/2)sinx
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Mia J.
its wrong06/03/21