Raymond B. answered 06/03/21
Tutor
5
(2)
Math, microeconomics or criminal justice
W=L-12
2W+2L = 78
W+L = 39
L-12 +L = 39
2L = 39+12 = 51
L = 51/2 = 25.5 cm long
W = 25.5-12 = 13.5 cm wide
Thamir S.
asked 06/03/21the perimeter of a rectangle is 78 cm the width is 12 cm less than the length create and solve an equation to determine the length of one side.
Raymond B. answered 06/03/21
Math, microeconomics or criminal justice
W=L-12
2W+2L = 78
W+L = 39
L-12 +L = 39
2L = 39+12 = 51
L = 51/2 = 25.5 cm long
W = 25.5-12 = 13.5 cm wide
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