The volumes of two similar solids are 40 in³ and 135 in³. If the surface area of the smaller solid is 48 in², what is the surface area of the larger solid?

Answer 1

x/48=135/40=27/8

x/6=27

x=162 in^2

but that's misleading

edge of larger = 135^1/3= 3(5^1/3)

surface area = 6 times 3(5^1/3) squared= 54(5^2/3)=about 157.90 not 162

edge of smaller=2(5^1/3)

surface area= 6 times 2(5^1/3) squared= 24(5^2/3)=about 70.18 not 48

larger edge= 1.5 times smaller edge

but sa ratio = 54/24= 9/4= 2.25, not 1.5 or 27/8=3.375