Solve the equation for (0</=theta<2pi) Answer ASAP

Question

2√3cosθsinθ=-3cosθ

Answer 1

2sqr3cosxsinx = -3cosx

2sqr3cosxsinx + 3cosx = 0

3cosx(2sqr3sinx +1) = 0

set each factor =0

3cosx = 0

cosx = 0

x = pi/2 = 90 degrees

or 3pi/2 = 270 degrees

2sqr3sinx =-1

sinx = -1/2sqr3 = -sqr3/6 = about 0.29 use a calculator with an inverse sine function

x= about -16.8 or 360-16.8 = 343.2 degrees

or 180+16.8 = 196.8 degrees

four solutions

x = 90, 196.8, 270 and 343.2 degrees