MATH questions and help

Question

Solving a value mixture problem using a linear equation

Answer 1

mix a Liters of x % with b Liters of y % yields c Liters of z%

ax + bx = cz

use a more specific example

mix an unknown amount of 60% and an unknown amount of 40% to get 100 Liters of 50%

.6x + .4(100-x) = .5(100)

.6x -.4x = .5(100)-.4(100)

.2x = .1(100)

x = 10/.2 = 50 Liters of 60%

(100-50) = 50 Liters of 40%

since 50% is midway between 40 and 50%

the amounts needed of each are equal