Raymond B. answered 08/10/23
Math, microeconomics or criminal justice
$40 per day
6 cents per mile
100 miles
$130 budget
how many days max
40d +.06m =130
m=100
40d= 130-6=124
d=124/40= 3.1 days
3 days max with $4 left over
Ashley C.
asked 05/31/21A rental car company charges $40 per day to rent a car and $0.06 for every mile driven. Aaden wants to rent a car, knowing that: He plans to drive 100 miles. He has at most $130 to spend. Write and solve an inequality that can be used to determine xx, the number of days Aaden can afford to rent while staying within his budget.
Raymond B. answered 08/10/23
Math, microeconomics or criminal justice
$40 per day
6 cents per mile
100 miles
$130 budget
how many days max
40d +.06m =130
m=100
40d= 130-6=124
d=124/40= 3.1 days
3 days max with $4 left over
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