The polynomial equation x(x2−25)(x2+2)=0 has how many real roots?

Answer 1

x(x²-25)(x²+2) = 0

x(x+5)(x-5)(x²+2) = 0

x = 0, 5, -5 are the real roots. x²+2 is positive for real values of x and has 2 imaginary roots.