If a random variable X follows exponential distribution with parameter λ = 2 ,then its probability density function is given by

Question

choose the correct answer

a. f (x)  2e2x , x  0

b. f (x)  12 e 12 x , x  0

c. f (x)  2e2x , x  0

d. f (x)  12 e 12 x , x  0

Answer 1

if X is an exponential random variable

then its pdf is given by: L * exp( -L * x)

L is lambda, which here it is 2.

so the pdf is: 2*exp(-2*x)