How do I solve (3 -3 sin x)(3+3 sinx)

Question

I got an answer of 3 sin²x+ 6sin x - 9

Answer 1

9 - 9 sin^2x = 9(1 - sin^2 x) = 9 cos^2x

9 cos^2x = 0x = implies cos x = 0, or x = π/2 +n π

Answer 2

Do you mean: (3 - 3sinx)(3 + 3sinx) = 0?

Then, 9 - 9sin²x = 0

sin²x = 1

sinx = 1 or -1

x = π/2 + kπ, where k = 0, 1, -1, 2, -2, ...