Raymond B. answered • 05/28/21

Math, microeconomics or criminal justice

h(t) = -16t^2 + 80t + 6 = height at time t

h'(t) =-32t+80 =0

t=80/32 = 5/2 = 2.5 seconds to reach max height

h(2.5) = -16(5/2)^2 + 80(5/2) + 6 = -100+200+6=106 ft = max height

h(t)=0 = -16t^2 + 80t + 6

8t^2 -40t -3 = 0

t= 40/16 + (1/16)sqr(1600+96) = 2.5+2.57 = 5.07 seconds to reach the floor

domain is t= 0 to about 5.07 seconds

range is h=6 to 106 feet