
Billy M. answered 05/28/21
Need a math tutor? I am a local Albany State Univ. math tutor
ℎ(𝑡)=―16𝑡2+64𝑡+80
t=-b/2a=-64/(-16)(2)= 2 sec
maximum height
h(2)= -16(2)^2+64(2)+80 = 144 ft
vertex of parabola
(2,144)
range
(-inf, 144]
Olha D.
asked 05/28/21Function , which gives the height in feet of ℎ(𝑡)=―16𝑡2+64𝑡+80projectile t seconds after it is launched. Find the vertex of its parabola, which gives the maximum height of the projectile, and use that to identify the range.
Billy M. answered 05/28/21
Need a math tutor? I am a local Albany State Univ. math tutor
ℎ(𝑡)=―16𝑡2+64𝑡+80
t=-b/2a=-64/(-16)(2)= 2 sec
maximum height
h(2)= -16(2)^2+64(2)+80 = 144 ft
vertex of parabola
(2,144)
range
(-inf, 144]
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Olha D.
Thank you very much05/30/21