using the identity (sin^2)x+(cos^2)x=1, find the value of (tan)x, to the nearest hundredth, if (cos)x=-0.32 and x is in Quadrant 2.

Answer 1

cosx =-0.32

sinx = sqr(1- 0.32^2) = sqr(1- .1024) = sqr0.8976 = about 0.9474

tanx = sinx/cosx = 0.9474/-0.32 = -2.9606 = -2.91 rounded to nearest hundredth