Inactive Tutor answered 05/26/21
(6,8) has opposite side = 8, adjacent side = 6
hypotenuse = sqr(8^2+6^2) = sqr(64+36) =sqr100 = 10
tanx = opposite side/adjacent side = 8/6 = 4/3
tanx = 43/
cosx = adjacent side/hypotenuse = 6/10 = 3/5
cosx = 3/5
Vanessa C.
asked 05/26/21Find the values of the basic trigonometric function for an angle in standard position passing through (6, 8)
find tanθ and cosθ
Inactive Tutor answered 05/26/21
(6,8) has opposite side = 8, adjacent side = 6
hypotenuse = sqr(8^2+6^2) = sqr(64+36) =sqr100 = 10
tanx = opposite side/adjacent side = 8/6 = 4/3
tanx = 43/
cosx = adjacent side/hypotenuse = 6/10 = 3/5
cosx = 3/5
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