A pool measuring 20 meters by 24 meters is surrounded by a path of uniform​ width. If the area of the pool and the path combined is 1760 square​ meters, what is the width of the​ path?

Answer 1

(20+2x)(24+2x) = 1760

4x^2 + 88x + 480 = 1760

x^2 +22x +120 = 440

x^2 +22x + 121 = 440-120+121

x+11 = sqr441

x = sqr441 -11 = 21-11 =

10 meters = width of the pool path