J.R. S. answered • 05/24/21

Ph.D. University Professor with 10+ years Tutoring Experience

Use ∆T = imK

∆T = change in freezing or boiling point = 13.8º for the freezing point

i = van't Hoff factor = 1 for a non electrolyte and since it doesn't state what the solute is, we assume this value

m = molality = ?

K = freezing or boiling constant for water = 0.52 for freezing point

We can now solve for m:

m = ∆T / (i)(K) = 13.8 / (1)(0.52) = 26.5 molal

Using this, we can now find the change in boiling point:

∆T = (1)(26.5 m)(1.86) = 49.4ºC

Boiling point of the solution would be 100 + 49.4 = 149.4ºC