Lamar rented a truck for one day. There was a base fee of $18.99, and there was an additional charge of 98 cents for each mile driven. Lamar had to pay 202.25 when he returned the truck.

Question

For how many miles did he drive the truck?

Answer 1

This problem would be an example of a linear relationship. The reason for this is because we are starting out with a flat fee, our y-intercept, and then our slope which is constant, 98 cents.

Let’s start with our equation y = mx + b where y is the resulting amount and x is miles.

we know that the total cost for renting was 202.25 so that’s our resulting amount which we can plug in for y.

We know our slope is going to be .98, we don’t know x, but we know that flat fee was $18.99

So we have 202.25 = .98x + 18.99 and from here you will find that x = 187 miles.

Answer 2

The easiest way to solve this problem is to set up an equation where x=miles driven. This equation would be 202.25 ($) = 18.99 (the one time charge) + .98 ($) *x, aka 202.25=18.99+.98x.

Remember to make your units equal to each other- you cannot use 98 because that is cents and 202.25 is in dollars; instead you have to use .98, because 98 cents=.98 dollars.

Now, you can just solve your equation:

202.25=18.99+.98x

-18.99 -18.99

183.26=.98x

/.98 /.98

187=x

So, your answer is 187 MILES (never forget units, teachers tend to be sticklers about that).

Hope this helps! :)

Answer 3

It is "202.25-18.99" divided by 0.98 which is 187 miles.