If sealed rigid 1.00 Liter container that holds 3.00 moles of gas is thrown into a 1450 degrees * C campfire what will the Internal pressure be?

Answer 1

PV = nRT

P = Pressure in pascals

V = Volume in cubic meters

n = moles of gas

R = gas constant = 8.314 J/Kmol

T = Temperature in Kelvins which is temperature in Celsius + 274 = 1724

P(.001m³) = (3 mols)(8.314J/Kmol)(1724 K)

P = 42,100,080 pascals