Start by writing down th4e formula for continuous compounding:
P(t) = P0ert
In your problem, P(t) = $1123.60, P0 = $1000, r is the rate we're trying to find, and t is the period that the money's in the bank
$1123.60 = $1000ert
$1123.60 / $1000 = ert
1.12360 = ert
To get the rate, r, out of the exponent take the log base e (ln) of both sides of the equation:
ln(1.12360) = rt
You didn't state what the time period, t, was in the problem. I'm guessing it's 1 year (t = 1):
ln(1.12360) = r
0.1165 = r which is 11.65%

Philip P.
05/21/21
Chloe M.
the time period is 2 years05/20/21