Sidney P. answered 05/22/21
Astronomy, Physics, Chemistry, and Math Tutor
1) A(t) = 1000(1 +.06)t and A(2) = $1123.60.
2) 1123.60 = P (1 +.05/4)4t and P = 1123.60/ (1.0125)8 = $1017.31.
3) 1123.60 = 1000(1 + r/12)12t, [(12 + r)/12]24 = 1.12360, (12 + r)/12 = (1.12360)1/24 = 1.00487,
12 + r = 12.0584 and r = .0584 = 5.84%.
4) 1123.60 = 1000(1 + .0475/6)6t, (1.0079167)6t = 1.12360. Take log or ln of both sides: log[(1.0079167)6t] = 6t log(1.0079167) = log(1.12360), 6t = 14.779, t = 2.463 years.