Raymond B. answered 08/19/23
Math, microeconomics or criminal justice
d= 18 km
at x km/hr =kph
d=rt, distance = rate of speed times time traveled
18 = rt
18= (r+30)(t-48) = (r+30)(t-4/5)
original speed = 15 kph and time = 1.2 minutes = 1 minute and 12 seconds
at 30 kph faster, new speed = 45 kph and new time = .4 minutes = 24 seconds
two equations two unknowns
use substitution, elimination, r=15, t= 6/5 hours. convert 48 minutes to 4/5 hours
18 = 15(6/5) =3x6
18 = (15+30)(6/5-4/5) = 45(2/5) = 9x2
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