Remember the 3 rules about logarithms that say,
1) log(xy) = log(x) + log(y)
2) log(x / y) = log(x) - log(y)
3) log(x^A) = A log(x)
We can use these 3 rules to manipulate the original expression,
log (x^13 y^8 / z^3)
= log(x^13) + log(y^8 / z^3) [using rule 1]
= log(x^13) + log(y^8) - log(z^3) [using rule 2]
= 13log(x) + 8log(y) - 3log(z) [using rule 3]
Therefore, A = 13, B = 8, C = -3