A line is parallel to y=4x-2 and intersects the point (5, -11). What is the equation of this parallel line?

Answer 1

plug in the values of x and y to the eq and solve for b.

y=mx+b

y=4x-2

-11=4(5)+b

b=-31

the answer is

y=4x-31

Answer 2

Existing line y = 4x - 2

Where slope m = 4

Parallel lines have the same slope. So, the slope of the new line is:

m = 4

Point (x₁, y₁) = (5, -11) is within the new line.

We have a Point and the Slope, so the equation of the line, in Point-Slope form is:

y - y₁ = m (x - x₁)

y - (-11) = 4 (x - 5)

y + 11 = 4x - 20

y = 4x - 20 -11

y = 4x - 31

The equation of the parallel line is y = 4x - 31