A line is parallel to y=2x-8 and intersects the point (-4, -1). What is the equation of this parallel line?

Answer 1

2 lines are parallel to each other only if they have the sane slope. so

y=mx +b is our line eq

y=2x-8

-1=2(-4)+b

b=7

so our answer is

Y=2x+7

the first part of our eq that represents the slope of our line stays the same. we only change the last part that represents our y- intersect (+b) .

Answer 2

A line is parallel to y=2x-8 and intersects the point (-4, -1). What is the equation of this parallel line?

Existing line y = 2x - 8

Where slope m = 2

Parallel lines have the same slope. So, the slope of the new line is:

m = 2

Point (x₁, y₁) = (-4, -1) is within the new line.

We have a Point and the Slope, so the equation of the line, in Point-Slope form is:

y - y₁ = m (x - x₁)

y - (-1) = 2 (x - (-4))

y +1 = 2 (x + 4)

y + 1 = 2x + 8

y = 2x + 8 - 1

y = 2x + 7

The equation of the parallel line is y = 2x + 7