What mass of copper will be produced from 250 mL of a 0.8 M copper (II) chloride solution?

Question

Equations would be greatly appreciated, biggest problem is that I've forgotten them and we're doing a year review.

Answer 1

Copper(II) chloride = CuCl₂

0.8 M CuCl₂ = 0.8 mols CuCl2 / L

250 ml = 0.250 L

moles CuCl₂ present = 0.8 mols / L x 0.250 L = 0.20 mols CuCl₂

mols Cu = 0.20 mols CuCl₂ x 1 mol Cu / mol CuCl₂ = 0.20 mols Cu

mass of Cu = 0.20 mols Cu x 63.55 g/mol = 12.71 g Cu = 10 g Cu (1 sig. fig.)