Inactive Tutor answered 05/17/21
Tutor
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The sum of the probabilities must be equal to 1. Then,
1/15 + k/15 + k/5 + 4/15 + k/15 = 1
5/15 + 5k/15 = 1
1/3 + k/3 = 1
k/3 = 2/3
k = 2
Don L.
asked 05/17/21X 1 2 3 4 5
p(x) 1/15 k/15 k/5 4/15 k/15
Inactive Tutor answered 05/17/21
The sum of the probabilities must be equal to 1. Then,
1/15 + k/15 + k/5 + 4/15 + k/15 = 1
5/15 + 5k/15 = 1
1/3 + k/3 = 1
k/3 = 2/3
k = 2
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