mathe is bo rang

Question

The product of a positive number and  more than twice that number is at most 

The inequality for this situation, where  represents the first number, is 

Which inequality represents all possible values of 

n≥8

n≤8

n≤9

n≥9

Answer 1

n x 2n= 2n^2 >0 because any number squared is positive,

a positive number squared >0

so among the choices you can seemingly eliminate 2nd and 3rd as they make n negative

but they don't as 0<n< 8 or 9 is still positive

there seems to be a number missing from the problem, right after "at most"

at most means an upper limit, so the actual answer has to be either the 2nd or 3rd choices

less than or equal to 8 or 9

if the missing word after "at most" was 162, then n<9 and 3rd choice is correct

if the missing word (number) after "at most" was 128, then n<8 and 2nd choice is correct

but in either choice, a full answer would be 0<n<8 or 9

it may seem "bo ring" but think of it as a detective's puzzle, searching for the hidden treasure and you get a big prize if you find it, such as an A+ on your homework and a rise in your GPA