What is the mass of magnesium (Mg) needed to react with 0.955 moles of silver nitrate (AgNO3). 2AgNO3 (s) + 1Mg (s) ⟶ 1Mg(NO3)2 (s) + 2Ag (s)

Answer 1

Based off of the chemical reaction, there are two moles of AgNO₃ for every one mole of Mg.

Therefore, 0.955 moles AgNO₃ will react with half as many moles of Magnesium.

We can see this by using dimensional analysis:

0.955mol AgNO₃ x 1 mol Magnesium = 0.4775mol Mg

2 mol AgNO₃

Next we have to find how many grams are in 0.4775 moles of Mg

Use the molar mass of Mg (24.31g/mol)

0.4775 mol Mg x 24.31g Mg = 11.61g Mg

1 mol Mg