Raymond B. answered 05/13/21
Math, microeconomics or criminal justice
I. x+y < 15
II. 5x + 10y > 100 divide by 5
x + 2y > 20
III. x< 4
IV. y > 11
inequalities I,III and IV create a solution set that is a right triangle with vertices (4,11), (0,11) and (0,15) inequality II is redundant and does not change the solution.
possible solutions are:
x=nickels y = dimes
4 11
3 11 or 12
2 11, 12 or 13
1 11, 12, 13, or 14
0 11, 12, 13, 14 or 15
15 different possibilities