What is an equation of the line that passes through the point (6,-4) and is perpendicular to the line 2x-y=5

Answer 1

2x - y= 5

solve for y

y=2x-5 when solved for y, the coefficient of the x term is the slope

the slope of a perpendicular line has the negative inverse of 2 which is -1/2

y=(-1/2)x + b is the perpendicular line, solve for b by plugging in the point (6,-4)

-4 =(-1/2)(6) + b

b = -4 + 6/2 = -1

y=-(1/2)x -1 multiply by 2

2y =-x -2

x+2y = -2 is the equation of a perpendicular line through (6,-4)