how many of each coin are there?

Question

There is a collection of nickels, dimes, and quarters. There are 5 more dimes than nickels and 5 more quarters than dimes. If the value of the collection is $26.20

Answer 1

d=5+n 5 more dimes than nickels

q =5+d = 5+5+n = 10+n

5 more quarters than dimes,

10 more quarters than nickels

q+d+n = 26.2, replace q with 10+n, d with 5+n

(10 +n) + (5+n) + n = 26.2

3n +15 = 26.2

3n = 26.2 -15 = 11.2

n= 11.2/3

n = 3.7333... nickels

which doesn't make sense as nickels come in whole numbers, integers

but go with it and calculate dimes and quarters

d = 5+n = 8.7333... dimes

q = 10+ n = 13.7333... quarters

add them 3.7333....+ 8.7333....+ 13.7333....

= 3+8+13 = 24

.7333... x 3 = 2.2

24+2.2 = 26.2

= 26.20

possibly there's a misprint or miscopy of the problem numbers

a problem with the problem