If X = 18 yards, Y = 80 yards, and Z = 82 yards, what is the sine of B?

Answer 1

18, 80 and 82 are sides of a right triangle

with angles 90, 77.32 and 12.68 degrees, approximately.

tan^-1(80/18) = 77.32

tan^-1(18/80) = 12.68

sin77.32= 0,98

sin12.68=0.22

sin^-1(80/82) =77.32

sin^-1(18/82) =12.68

sinB is either 80/82 = 0.98

or 18/82 = 0.22