Raymond B. answered 05/07/21
Math, microeconomics or criminal justice
1372 km against the wind
1552 with the wind
d=rt, distance = rate of speed times time, t= d/r, t=2
let p = speed of plane in still air, w = speed of the wind
2=1372/(p-w)
2p-2w -1372, p-w= 686,
p = 686+w
2 = 1372/(p-w) = 1552/(p+w)
1372(p+w) = 1552(p-w)
1372p + 1372w = 1552p - 1552w
(1552-1372)p = (1552+1372)w
180p = 2924w
180(686+w) = 2924w
2924w-180w = 180(686)
w = 180(686)/2744 = 45km/hr = wind speed
p = 686+45 = 731 km per hr= plane speed in still air