The sum of three consecutive integers is 66, set up an equation that describes this problem

Answer 1

x = 66/3 = 22 = the middle integer of 3 consecutive integers

x-1 = 21

x = 22

x+1 = 23

they sum to 66

(x-1) + x + (x+1) = 66

3x = 66

x = 66/3