1/2 + 2x=3 3y=4x+10 solve by substitution

Answer 1

2x+ 1/2 = 3

2x = 3-1/2 = 6/2-1/2 = 5/2

x =(5/2)/2 = 5/4

x=5/4= 1.25

3y=4x+10

3y=4(5/4) +10 =5+10 =15

y = 15/3 = 5

solution is (5/4, 5)

UNLESS, maybe you left out a "y" after the 1/2 in the 1st equation?

Usually these problems have both variables in both equations

(1/2)y +2x = 3

multiply by 6

3y +12x = 18, subtract to eliminate the y variable

3y-4x = 10

16x=8

x=1/2

3y-4(1/2) = 10

3y =10+2

y =12/3 = 4

solution is (1/2,4)