Raymond B. answered 05/04/21
Math, microeconomics or criminal justice
Permutations involve factorials. nPr = n!/r! = for example 5 choose 2 = 5!/2! = 5x4x3x2!/2! = 5x4x3 = 60 outcomes. n! = nx(n-1)x(n-2)....x1. For combinations, there's more factorials, but a smaller result: nCr = n!/r!(n-r)!
exponents are "with replacement" problems. roll a die with 6 sides 3 times, chances of getting 3 ones or 3 of any outcome is (1/6)^3=(1/6)(1/6)(1/6 = 1/216
Or there's 6 marbles in a bag. You randomly pick one, replace it, pick again, replace it and pick a marble a 3rd time. Odds of 3 of a kind, if each marble is a different color is 1/216. Flip a coin twice. Odds of 2 tails is (1/2)^2 = 1/4