Assume that you are drawing two balls without replacement from an urn that contains 11 green​ balls 5 blue​ balls and 3 red balls what is the probability that you will draw a red ball and a blue ​ball

Question

Round to three decimal places as needed

Answer 1

11G, 5B, 3R

total 19

Pr(R) = 3/19

Pr(R then B) = 3/19 x 5/18 = 15/(19)(18) = 5/(19)(6) = 5/114 = about 0.044

but another way to get one red and one blue is

Pr(B) = 5/19

Pr(B then R) = 3/18 x 5/19 = about .044

Pr(B and R) = 2(5)/144 = .044 + .044 = .088