Solve 5sin𝑥 = 3sin𝑥 + √3 on the interval [0,2𝜋)

Answer 1

5sinx = 3sinx + sqr3

subtract 3sinx from both sides

2sinx = sqr3,

divide by 2

sinx =(1/2)sqr3 = about 0.866

x= 60 degrees or pi/3 radians in quadrant I

x also = 120 degrees or 2pi/3 in quadrant II

use a calculator with an inverse trig function